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Question

Two particles of masses m and 4m have kinetic energies in the ratio of 2:1. What is the ratio of their linear momenta?

Moderate
Solution

 Given (KE)1=12m1v12=2K

 and (KE)2=12m2v22=K, so that 

m1v12m2v22=2m12v12m22v22=2m1m2p1p2=2m1m2=24=12 m2=4m1

Hence the correct choice is (a)

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