Two particles of masses m and 4m have kinetic energies in the ratio of 2:1. What is the ratio of their linear momenta?
12
14
116
Given (KE)1=12m1v12=2K
and (KE)2=12m2v22=K, so that
m1v12m2v22=2m12v12m22v22=2m1m2p1p2=2m1m2=24=12 ∵m2=4m1
Hence the correct choice is (a)