First slide
Universal law of gravitation
Question

Two particles of masses m1 and m2, m1 > m2 move in circular paths under the action of their gravitational attraction. While doing so, their separation remains constant and equals 'r' . Radius of circular path of m2 is:

Easy
Solution

m1 and m2 move in circular paths about their centre of mass.
So, r2=m1m1+m2r

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