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Questions  

Two particles of masses m1 and m2, m1 > m2 move in circular paths under the action of their gravitational attraction. While doing so, their separation remains constant and equals 'r' . Radius of circular path of m2 is:

a
r2
b
m1m2r
c
m2m1+m2r
d
m1m1+m2r

detailed solution

Correct option is D

m1 and m2 move in circular paths about their centre of mass.So, r2=m1m1+m2r

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