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Two particles of masses m1 and m2 move with initial velocities u1 and u2. On collision, one of the particles get excited to higher level, after absorbing energy ε. If final velocities of particles be v1 and v2, then we must have [CBSE AIPMT 2015]

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a

m12u1+m22u2-ε=m12v1+m22v2

b

12m1u12+12m2u22=12m1v12+12m2v22-ε

c

12m1u12+12m2u22-ε=12m1v12+12m2v22

d

12m12u12+12m22u22+ε=12m12v12+12m22v22

answer is C.

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Detailed Solution

Total initial energy =12m1u12+12m2u22Since, after collision one particle absorbs energy ε.∴ Total final energy =12m1v12+12m2v22+εFrom conservation of energy, 12m1u12+12m2u22=12m1v12+12m2v22+ε⇒ 12m1u12+12m2u22-ε=12m1v12+12m2v22

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Two particles of masses m1 and m2 move with initial velocities u1 and u2. On collision, one of the particles get excited to higher level, after absorbing energy ε. If final velocities of particles be v1 and v2, then we must have [CBSE AIPMT 2015]