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Two particles of masses $m_{1}, m_{2}$ move with initial $u_{1} a n d u_{2}$ . On collision, one of the particles get excited to higher level, after absorbing energy $ε$ . If final velocities of particles be $ν_{1} a n d ν_{2}$ then we must have

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12m1u12+12m2u22-ε=12m1v12+12m2v22

12m12u12+12m22u22+ε=12m12v12+12m22v22

m12u1+m22u2-ε=m12v1+m22v2

12m1u12+12m2u22=12m1v12+12m2v22-ε

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Correct option is A

Total initial energy of two particles =12m1u12+12m2u22Total final energy of two particles =12m2v22+12m1v12+εUsing energy conservation principle, 12m1u12+12m2u22=12m1v12+12m2v22+ε∴ 12m1u12+12m2u22-ε=12m1v12+12m2v22

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Two particles of masses m1,m2 move with initial u1 and u2. On collision, one of the particles get excited to higher level, after absorbing energy ε. If final velocities of particles be ν1 and ν2 then we must have

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Two particles of masses $m_{1}, m_{2}$ move with initial $u_{1} a n d u_{2}$ . On collision, one of the particles get excited to higher level, after absorbing energy $ε$ . If final velocities of particles be $ν_{1} a n d ν_{2}$ then we must have