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Q.

Two particles of masses m1,m2 move with initial u1 and u2.  On collision, one of the particles get excited to higher level, after absorbing energy ε. If final velocities of particles be ν1 and ν2  then we must have

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a

12m1u12+12m2u22-ε=12m1v12+12m2v22

b

12m12u12+12m22u22+ε=12m12v12+12m22v22

c

m12u1+m22u2-ε=m12v1+m22v2

d

12m1u12+12m2u22=12m1v12+12m2v22-ε

answer is A.

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Detailed Solution

Total initial energy of two particles =12m1u12+12m2u22Total final energy of two particles =12m2v22+12m1v12+εUsing energy conservation principle, 12m1u12+12m2u22=12m1v12+12m2v22+ε∴  12m1u12+12m2u22-ε=12m1v12+12m2v22
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