Two particles of masses $$m1$$ and $$m2$$ in projectile motion have velocities v→$$1$$ and v→$$2$$ respectively at time t $$=$$ $$0$$. They collide at time $$t0$$ . Their velocities become v→$$11$$ and v→$$21$$ at time $$2t0$$ while still moving in air. The value of $$m1v$$→$$11+m2v$$→$$21$$−$$m1v$$→$$1+m2v$$→$$2$$ is

Question

Two particles of masses $$m1$$ and $$m2$$ in projectile motion have velocities v→$$1$$ and v→$$2$$ respectively at time t $$=$$ $$0$$. They collide at time $$t0$$ . Their velocities become v→$$11$$ and v→$$21$$ at time $$2t0$$ while still moving in air. The value of $$m1v$$→$$11+m2v$$→$$21$$−$$m1v$$→$$1+m2v$$→$$2$$ is

Infinity Learn · Accepted Answer

$$mv1=m(u+at)m1v11+m2v21=mv1+2gt0+mv2+2gt0$$

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Two particles of masses m1 and m2 in projectile motion have velocities v→1 and v→2 respectively at time t = 0. They collide at time t0 . Their velocities become v→11 and v→21 at time 2t0 while still moving in air. The value of m1v→11+m2v→21−m1v→1+m2v→2 is

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