Two particles of masses m and 2 m with charges 2q and 2q are placed in a uniform electric field E and allowed to move for the same time. The ratio of their kinetic ener8ies will be
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a
2 : 1
b
8 : 1
c
4 : 1
d
1 : 4
answer is A.
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Detailed Solution
a1=2qEm and a2=2qE2m ∴ a1=2a2 K1=12m1v12=12m1a1t2 (∵v=u+at) K2=12m2v22=12m2a2t2∴ K1K2=m1a12m2a22=m2m×41=21.