First slide

Electric field

Question

Two particles of masses in the ratio 1 : 2, with charges in the ratio 1 : 1, are placed at rest in a uniform electric field. They are released and allowed to move for the same time. The ratio of their kinetic energies will be finally

Moderate

A

2:1
B

8:1
C

4:1
D

1:4

Solution

As charge on both particles is same, so electric force acting on them will be same. Since the particles are allowed to move for the same time, their final momentum will be same. Because change in momentum = impulse - force x time, so
$\begin{array}{l} KE = \frac{p^{2}}{2 m} gives KE \propto \frac{1}{m} \\ \frac{{KE}_{1}}{K E_{2}} = \frac{m_{2}}{m_{1}} = 2 : 1 \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App