Two particles move parallel to the x-axis about the origin with same amplitude 'a' and frequency ω. At a certain instant they are found at a distance a/3 from the origin on opposite sides but their velocities are in the same direction. What is the phase difference between the two?
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a
cos−179
b
cos−159
c
cos−149
d
cos−119
answer is A.
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Detailed Solution
Let x1=asinωt and x2=asin(ωt+δ) be two SHMs. a3=asinωt and −a3=asin(ωt+δ)sinωt=1/3 and sin(ωt+δ)=−1/3 Eliminating t,13cosδ+1−19sinδ=−139cos2δ+2cosδ−7=0cosδ=−1 or 79i.e., δ=180∘ or cos−179If we put 180o, we find that v1 and v2 are of opposite signs.Hence δ = 180o is not applicable.∴ δ=cos−179