Q.

Two particles move in a uniform gravitational field with an acceleration g. At the initial moment the particles were located at same point and moved with velocities  u1 = 9ms-1 and  u2= 4m s-1 horizontally in opposite directions. The time between the particles at the moment when their velocity vectors are mutually perpendicular in s is (take g = 10 m s-2)

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a

0.36

b

3.6

c

0.6

d

6

answer is C.

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Detailed Solution

t=u1u2 g
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