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Questions  

Two particles P and Q are located at distance rp and rQ respectively from the centre of rotating disc such that rp > rQ. The disc is rotating with constant angular acceleration. We can say

a
both P and Q have the same acceleration
b
both P and Q do not have any acceleration
c
P has greater acceleration than Q
d
Q has greater acceleration than P

detailed solution

Correct option is C

Resultant acceleration,a = ar2+at2 = (ω2r)2+(rα)2⇒  a = r(ω2)2+α2As ω and α will be same for both the particles P and Q, hence aP>aQ(rp>rQ)

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