Question

Two particles P and Q are located at distance $r_{p} and r_{Q}$ respectively from the centre of rotating disc such that $r_{p} > r_{Q}$ . The disc is rotating with constant angular acceleration. We can say

Moderate

Solution

Resultant acceleration,
a = $\sqrt{{a_{r}}^{2} + {a_{t}}^{2}} = \sqrt{{(ω^{2} r)}^{2} + {(rα)}^{2}}$
$\Rightarrow a = r \sqrt{{(ω^{2})}^{2} + α^{2}}$
As $ω$ and $α$ will be same for both the particles P and Q, hence $a_{P} > a_{Q} (r_{p} > r_{Q})$

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