Two particles P and Q describe SHM of same amplitude a, same frequency f along the same straight line. The maximum distance between the two particles is a2.The phase difference between the particle is

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zero

π2

π6

π3

answer is B.

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Detailed Solution

x1=asin⁡ωt+ϕ1x2=asin⁡ωt+ϕ2⇒ x1−x2=2asin⁡ωt+ϕ1+ϕ22cos⁡ϕ1−ϕ22 To maximize x1−x2:sin⁡ωt+ϕ1+ϕ22=1⇒ a2=2a×1×cos⁡ϕ1−ϕ22⇒ 12=cos⁡ϕ1−ϕ22⇒ π4=ϕ1−ϕ22⇒ϕ1−ϕ2=π2

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