Two particles P and Q simultaneously start moving from point A with velocities 15 ms-1 and 20 ms-1 respectively. The two particles move with accelerations equal in magnitude but opposite in direction. When P overtakes Q at B, then its velocity is 30 ms-1. The velocity of Q at point B will be
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a
30 ms-1
b
5 ms-1
c
20 ms-1
d
15 ms-1
answer is B.
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Detailed Solution
For P, 30 =15 + at or at = 15 ms-1For Q,v = 20 - at or v = 20 - 15 = 5 ms-1