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Q.

Two particles P and Q start from rest and move for equal time on a straight line. Particle P has an acceleration of X m/s2 for the first half of the total time and 2 Xm/s2 for the second half. The particle Q has an acceleration of 2 X m/s2 for the first half of the total time and X m/s2 for the second half. Which particle has covered longer distance?

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a

both have covered the same distance

b

P has covered the larger distance

c

Q has covered the larger distance

d

none of these

answer is C.

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Detailed Solution

For P, in t sec.x1 = 12Xt2 = Xt22   ⇒v1= Xtx2 = (Xt)t +122Xt2       ⇒ x2 = 2Xt2xp = x1+x2 = 52X+2For Q,y1 = 12(2X)t2 = Xt2        ⇒  v2 = 2Xty2 = (2Xt)t +12Xt2 = 52Xt2yQ = y1+y2 = 72Xt2  ⇒yQ >xp
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Two particles P and Q start from rest and move for equal time on a straight line. Particle P has an acceleration of X m/s2 for the first half of the total time and 2 Xm/s2 for the second half. The particle Q has an acceleration of 2 X m/s2 for the first half of the total time and X m/s2 for the second half. Which particle has covered longer distance?