Two particles P and Q start from rest and move for equal time on a straight line. Particle P has an acceleration of X m/s2 for the first half of the total time and 2X m/s2 forthe second half. The particle Q has an acceleration of 2X m/s2 for the first half of the total time and Xm/s2 for the second half. Which particle has covered larger distance?

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both have covered the same distance

P has covered the larger distance

Q has covered the larger distance

none of these

answer is C.

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Detailed Solution

For P, in tsec. x1=12Xt2=Xt22⇒v1=Xtx2=(Xt)t+122Xt2⇒x2=2Xt2xp=x1+x2=52X+2 For Q, y1=12(2X)t2=Xt2⇒v2=2Xty2=(2Xt)t+12Xt2=52Xt2yQ=y1+y2=72Xt2⇒yQ>xP

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