Q.

Two particles performing simple harmonic motion with amplitude A and frequency f along the same line. They cross each other while travelling in opposite directions when their displacement is half of their amplitude. The phase difference between them is

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a

30°

b

60°

c

90°

d

120°

answer is D.

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Detailed Solution

y=asin⁡ωt+ϕ0. According to questiony=a2⇒a2=asin⁡ωt+ϕ0⇒ωt+ϕ0=ϕ=π6 or 5π6Physical meaning of π6: Particle is going towards extreme position.Physical meaning of 5π6: Particle is going towards mean position.So phase differenceΔϕ=5π6−π6=2π3rad=120∘
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Two particles performing simple harmonic motion with amplitude A and frequency f along the same line. They cross each other while travelling in opposite directions when their displacement is half of their amplitude. The phase difference between them is