Two particles performing simple harmonic motion with amplitude A and frequency f along the same line. They cross each other while travelling in opposite directions when their displacement is half of their amplitude. The phase difference between them is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
30°
b
60°
c
90°
d
120°
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
y=asinωt+ϕ0. According to questiony=a2⇒a2=asinωt+ϕ0⇒ωt+ϕ0=ϕ=π6 or 5π6Physical meaning of π6: Particle is going towards extreme position.Physical meaning of 5π6: Particle is going towards mean position.So phase differenceΔϕ=5π6−π6=2π3rad=120∘