Two particles of same mass are projected simultaneously with same speed 20 ms–1 from the top of a tower of height 20m. One is projected vertically upwards and other projected horizontally. The maximum height attained by centre of mass from the ground will be (g = 10 ms–2)

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10√2m

25m

25√2m

answer is B.

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Detailed Solution

from ground COM distance = h + Hmax= 20 + 5 = 25m