Two particles of same time period (T) and amplitude undergo SHM along the same line with initial phase of π$$6$$. lf they start at the same instant and at same point along opposite directions. Find the time after which they will meet again for the first time:

Question

Two particles of same time period (T) and amplitude undergo SHM along the same line with initial phase of π$$6$$. lf they start at the same instant and at same point along opposite directions. Find the time after which they will meet again for the first time:

Infinity Learn · Accepted Answer

x $$=$$ $$Asin($$ω$$t+$$ϕ$$)$$         ϕ $$=$$ π$$6$$         x $$=$$ $$Asin($$ω×$$0+$$π$$6)$$ $$=$$ $$A2$$        Time taken in moving $$A2$$ $$=$$ $$T8It$$ is obvious that particles will meet again at Q while having covered a $$distance=$$ $$4$$×A $$2$$ $$=$$ $$2$$ A

Two particles of same time period (T) and amplitude undergo SHM along the same line with initial phase of $\frac{π}{6}$ . lf they start at the same instant and at same point along opposite directions. Find the time after which they will meet again for the first time:

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Two particles of same time period (T) and amplitude undergo SHM along the same line with initial phase of π6. lf they start at the same instant and at same point along opposite directions. Find the time after which they will meet again for the first time:

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Ready to Test Your Skills?

free study material

Two particles of same time period (T) and amplitude undergo SHM along the same line with initial phase of $\frac{π}{6}$ . lf they start at the same instant and at same point along opposite directions. Find the time after which they will meet again for the first time: