Two particles start moving simultaneously from the same point and execute simple harmonic motion along the same line. Distances of the particle from their equilibrium position are $$x1=4cos4$$$$π$$t cm and $$x2=4cos4$$$$π$$$$t+$$π$$3cm$$. Then maximum separation between the particles is

Question

Two particles start moving simultaneously from the same point and execute simple harmonic motion along the same line. Distances of the particle from their equilibrium position are $$x1=4cos4$$$$π$$t cm and $$x2=4cos4$$$$π$$$$t+$$π$$3cm$$. Then maximum separation between the particles is

Infinity Learn · Accepted Answer

Particles are oscillating with same frequency and the phase difference between them is π$$3$$. From the phasor diagram it is evident that separation between the particle M and N is maximum when their respective reference particles P and Q are symmetrically placed about the $$y-axis$$.∴ Maximum separation $$=OM+ON=4sin$$$$π$$$$6+4sin$$$$π$$$$6cm=4$$ cm

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Two particles start moving simultaneously from the same point and execute simple harmonic motion along the same line. Distances of the particle from their equilibrium position are x1=4cos4πt cm and x2=4cos4πt+π3cm. Then maximum separation between the particles is

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