Two particles whose masses are 30 kg and 10 kg and their position vectors are −ı^−ȷ^−k^ and i^+j^+k^ respectively would have the centre of mass at position :
−(ı^+ȷ^+k^)/2
ı^+ȷ^+k^/2
−(ı^+ȷ^+k^)/4
(ı^+ȷ^+k^)/2
∵ R→cm=m1r→1+m2r→2m1+m2
=10(i^+j^+k^)+30(−i^−j^−k^)10+30
=10i^+10j^+10k^−30i^−30j^−30k^40
=−20i^−20j^−20k^40
R→cm=−(i^+j^+k^)2