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Q.

Two particles whose masses are 30 kg and 10 kg and their position vectors are −ı^−ȷ^−k^ and i^+j^+k^ respectively would have the centre of mass at position :

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a

−(ı^+ȷ^+k^)/2

b

ı^+ȷ^+k^/2

c

−(ı^+ȷ^+k^)/4

d

(ı^+ȷ^+k^)/2

answer is A.

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Detailed Solution

∵    R→cm=m1r→1+m2r→2m1+m2=10(i^+j^+k^)+30(−i^−j^−k^)10+30=10i^+10j^+10k^−30i^−30j^−30k^40=−20i^−20j^−20k^40R→cm=−(i^+j^+k^)2
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