First slide

Doppler

Question

Two passenger trains moving with a speed of 108 km/ hour cross each other. One of them blows a whistle whose frequency is 750 Hz. If speed of sound is 330 m/s, then after the trains cross each other, the passengers sitting in the other train will hear sound whose frequency will be

Moderate

A

900 Hz
B

625 Hz
C

750 Hz
D

800 Hz

Solution

$n^{'} = n (\frac{v - v_{o}}{v + v_{s}}) = 750 (\frac{330 - 180 \times \frac{5}{18}}{330 + 108 \times \frac{5}{18}}) = 625 Hz$

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