Two pendulum start oscillating in the same direction at the same time from the same mean position. Their time periods are respectively $$2$$ s and $$1.5$$ s. The phase difference between them, when the smaller pendulum has completed one vibration, will be

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Infinity Learn · Accepted Answer

Smaller pendulum will be that for which time period is less, here $$1.5$$ s. So when this completes one vibration, the bigger pendulum will complete its $$34$$ oscillation (because$$ its time period is $$2$$ $$s) i.e., it will be at its negative extreme position. Hence the smaller pendulum will be ahead by a phase of π$$2$$ than bigger pendulum at this time.

Two pendulum start oscillating in the same direction at the same time from the same mean position. Their time periods are respectively 2 s and 1.5 s. The phase difference between them, when the smaller pendulum has completed one vibration, will be

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