Questions
Two pendulums have time periods T and 5T/4. They start S.H.M. at the same time from the mean position. What will be the phase difference between them after the bigger
pendulum has complete one oscillation?
detailed solution
Correct option is B
As 5T4=T+T4By the time, the bigger pendulum makes one full oscillation, the smaller pendulum will make 1+14 oscillation. The bigger pendulum will be in the mean position and the smaller one will be in the positive extreme position. Thus, phase difference = 90oTalk to our academic expert!
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A simple pendulum has time period T1. The point of suspension is now moved upward according to equation where . If new time period is T2 then ratio will be
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