Questions
Two persons A and B each carrying a source of sound of frequency , are standing a few meters a part in a quiet field, ‘A’ starts moving towards ‘B’ with a speed of .If V be the speed of sound then the number of beats heard per second by A will be
detailed solution
Correct option is A
Person A hears the sound of his own source whose frequency γ . He also hears the sound of source carried by person B γ1=γ1+u/v Hence, No. of beats heard γ1−γ=γuvAPPARENT FREQUENCY of source with B received by the person A will be given by n' =nv-vov-vshere vo=-u and vs=0Similar Questions
A source of sound having natural frequency f0 = 1800 Hz is moving uniformly along a line separated from a stationary listener by a distance l = 250 m. The velocity of source is n = 0.80 times the velocity of sound. Find the frequency of sound (in Hz) received by the listener at the moment when the source gets closest to him.
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