Two persons A and B each carrying a source of sound of frequency γ , are standing a few meters a part in a quiet field, ‘A’ starts moving towards ‘B’ with a speed of u .If V be the speed of sound then the number of beats heard per second by A will be

Question

Two persons A and B each carrying a source of sound of frequency γ , are standing a few meters a part in a quiet field, ‘A’ starts moving towards ‘B’ with a speed of u .If V be the speed of sound then the number of beats heard per second  by A will be

Infinity Learn · Accepted Answer

Person A hears the sound of his own source whose frequency γ . He also hears the sound of source carried by person B γ$$1=$$γ$$1+u/v$$                 Hence,  No. of beats heard γ$$1$$−γ$$=$$γuvAPPARENT FREQUENCY  of source with B received by the person A will be given by n' $$=nv-vov-vshere$$ $$vo=-u$$ and $$vs=0$$

Two persons A and B each carrying a source of sound of frequency $γ$ , are standing a few meters a part in a quiet field, ‘A’ starts moving towards ‘B’ with a speed of $u$ .If V be the speed of sound then the number of beats heard per second by A will be

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