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Q.

Two persons Ram and Shyam are throwing ball at each other as shown in the figure. The maximum horizontal distance from the building where Ram can stand and still throw a ball a Shyam is d1. The maximum horizontal distance of Ram from the building where Shyam can throw a ballis da. If both of them can throw ball with a velocity of 2gh, find out the ratio of d22d12.Neglect the height of each person.

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answer is 3.

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Detailed Solution

y=xtan⁡θ−gx22u2sec2⁡θWhen Ram throws the ball,       h=xtan⁡θ−gx22(2gh)21+tan2⁡θtan2⁡θ−8hxtan⁡θ+1+8h2x2=0For real roots,              D≥0⇒8hx2−4(1    +8h2x22≥0⇒    x≤8h⇒    xmax=8h        d1=8hWhen Shyam throws the ball,y=xtan⁡θ−gx22u2cos2⁡θ⇒ −h=xtan⁡θ−gx22(2gh)2sec2⁡θ⇒tan2⁡θ−8hxtan⁡θ+1−8h2x2=0For real roots,          D≥0 8hx2−41−8h2x2≥0    x≤24h    xmax=24h   d2=24h   d22d12=24h8h2=3
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