Two plane mirrors are inclined to each other at an angle θ. A ray of light is incident an one mirror and after two successive reflections, the final reflected ray becomes parallel to the incident ray. Then the value of θ is

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Any angle

90o

45o

60o

answer is B.

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Detailed Solution

∠ABO=π−α+θ∠RBO=π−α+θAlso, by law of reflection, ∠PBM2=∠ABO=π−α+θSince PB and QA are parallel, ∠QAB=∠PBR⇒π−2α=2π−α+θ⇒θ=90o

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