Two plane mirrors, a source S of light, emitting monochromatic rays of wavelength λ and a screen are arranged as shown in figure. If angle θ is very small, the fringe width of interference pattern formed on screen by reflected rays is:
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a
a+bλ4aθ
b
2a+bλaθ
c
2a+bλ4aθ
d
a+bλaθ
answer is C.
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Detailed Solution
β=λDd=λ2acos2θ+b4acosθsinθ for small values of θ, sinθ≈0 cosθ≈1 ⇒β=λ2a+b4aθ