First slide

Electrostatic potential

Question

Two plates are 2 cm apart. A potential difference of 10 volt is applied between them. The electric field between the plates is

Easy

A

20 N/C
B

500 N/C
C

5 N/C
D

250 N/C

Solution

$E = \frac{V}{d} = \frac{10}{2 \times 10^{- 2}} = 500 N / C$

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