Two point charges of 20 μC and 80 μC are 10 cm apart. Where will the electric field strength be zero on the line joining the charges from 20 μC charge

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0.1 m

0.04 m

0.033 m

0.33 m

answer is C.

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Detailed Solution

Let neutral point be obtained at a distance x from 20 μC charge. Hence at neutral point 20(x)2=80(10−x)2⇒x=+0.033m

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