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Q.

Two point charges +3μC and +8μC repel each other with a force of 40 N. If a charge of −5μC is added to each of them, then the force between them will become

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a

- 10 N

b

+10 N

c

+ 20 N

d

- 20 N

answer is A.

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Detailed Solution

Here, F=40=k(3)(8)r2=24kr2 and  F′=k(3−5)(8−5)r2=k(−2)(3)r2=−6kr2∵ F′F=−6kr2×r224k=−14⇒ F′=−F4=−404=−10 N
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