First slide

Electrostatic force

Question

Two point charges placed at a certain distance r in air exert a force F on each other. Then the distance r' at which these charges will exert the same force in a medium of dielectric constant k is given by

Easy

A

r
B

r/k
C

$r / \sqrt{k}$
D

$r \sqrt{k}$

Solution

$F = F'$ $or \frac{Q_{1} Q_{2}}{4 {πε}_{0} r^{2}} = \frac{Q_{1} Q_{2}}{4 {πε}_{0} r'^{2} K} \Rightarrow r' = \frac{r}{\sqrt{K}}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App