First slide

Coulumbs law

Question

Two point charges placed at a certain distance r in air exert a force F on each other. Then, the distance r' at which these charges will exert the same force in a medium of dielectric constant k is given by

Moderate

A

r
B

r/k
C

$r / \sqrt{k}$
D

r $\sqrt{K}$

Solution

In air : $F = \frac{1}{4 {πε}_{0}} \frac{q_{1} q_{2}}{r^{2}}$
In Medium : $F = \frac{1}{4 πεkr'^{2}} \Rightarrow {({Kr}^{'})}^{2} = r^{2} \Rightarrow r^{'} = \frac{r}{\sqrt{K}}$

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