Two point charges q1=2μC and q2=1 μC are placed at distances b=1cm and a=2cm from the origin on the Y and X axes as shown in figure. The electric field vector at point P(a,b) will subtend an angle θ with the X-axis is given by tanθ=

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answer is 2.

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Detailed Solution

tanθ=E2E1=Kq2b2Kq1a2=12×212=2

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