First slide

Electric field

Question

Two point charges $q_{1} = 2 μ C a n d q_{2} = 1 μ C$ are placed at distances b=1cm and a=2cm from the origin on the Y and X axes as shown in figure. The electric field vector at point P(a,b) will subtend an angle $θ$ with the X-axis is given by tan $θ$ =

Moderate

Solution

$\tan θ = \frac{E_{2}}{E_{1}} = \frac{\frac{K q_{2}}{b^{2}}}{\frac{K q_{1}}{a^{2}}} = \frac{1}{2} \times {(\frac{2}{1})}^{2} = 2$

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