First slide

Electric field

Question

Two Point Charges q_A=3 $μC$ and $q_{B} = - 3 μC$ are located 20 cm apart in vacuum. What is the electric field at the midpoint O of the line AB joining the two charges?

Moderate

A

$1.2 \times 10^{6} N / C$
B

$5.4 \times 10^{6} N / C$
C

$6.9 \times 10^{6} N / C$
D

$9.9 \times 10^{6} N / C$

Solution

The electric field at midpoint O (as shown in the following figure) can be expressed as

$\begin{array}{l} E_{net} = E_{A} + E_{B} = \frac{(9 \times 10^{9}) (3 \times 10^{- 6})}{(0 .1)^{2}} + \frac{(9 \times 10^{9}) (3 \times 10^{- 6})}{(0 .1)^{2}} \\ = 5 .4 \times 10^{6} N / C \end{array}$

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