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A two point charges 4q and $- q$ are fixed on the x-axis at $x = - \frac{d}{2}$ and $x = \frac{d}{2}$ , respectively. If a third point charge ‘q’ is taken from the origin to x = d along the semicircle as shown in the figure, the energy of the charge will :

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increase by 3q24π∈0d

decrease by q24π∈0d

decrease by 4q23π∈0d

increase by 2q23π∈0d

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detailed solution

Correct option is C

The change is only due to 4qCharge q distance from "−q" is not changing.So Δ U=4qq4π∈013d/2−1d/2 =−4q23π∈0d

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A two point charges 4q and − q are fixed on the x-axis at x=−d2 and x=d2, respectively. If a third point charge ‘q’ is taken from the origin to x = d along the semicircle as shown in the figure, the energy of the charge will :

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Ready to Test Your Skills?

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A two point charges 4q and $- q$ are fixed on the x-axis at $x = - \frac{d}{2}$ and $x = \frac{d}{2}$ , respectively. If a third point charge ‘q’ is taken from the origin to x = d along the semicircle as shown in the figure, the energy of the charge will :