A two point charges 4q and  $-q$ are fixed on the x-axis at  $x=-\frac{d}{2}$ and  $x=\frac{d}{2}$, respectively. If a third point charge ‘q’ is taken from the origin to x = d along the semicircle as shown in the figure, the energy of the charge will :

• A

  increase by $\frac{3q^2}{4\pi {\in }_{0}d}$

• B

  decrease by  $\frac{q^2}{4\pi {\in }_{0}d}$

• C

  decrease by $\frac{4q^2}{3\pi {\in }_{0}d}$

• D

  increase by  $\frac{2q^2}{3\pi {\in }_{0}d}$