A two point charges 4q and − q are fixed on the x-axis at x=−d2 and x=d2, respectively. If a third point charge ‘q’ is taken from the origin to x = d along the semicircle as shown in the figure, the energy of the charge will :
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a
increase by 3q24π∈0d
b
decrease by q24π∈0d
c
decrease by 4q23π∈0d
d
increase by 2q23π∈0d
answer is C.
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Detailed Solution
The change is only due to 4qCharge q distance from "−q" is not changing.So Δ U=4qq4π∈013d/2−1d/2 =−4q23π∈0d