Two point charges +Q and −Q2 are kept at a separation and potential energy at the mid point joining the charges is -0.8 U. Now +2Q charge is added to each of the point charge. Then potential energy at the same point has a magnitude of
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a
3.2 U
b
2.4 U
c
3.6 U
d
7.2 U
answer is D.
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Detailed Solution
Initially, U=K(+Q)(−Q2)d=−12KQ2dFinally U1=K(+3Q)(2Q−Q2)d=92.KQ2d⇒U1=9×0.8U=7.2 U