Questions
Two point charges +Q and are kept at a separation and potential energy at the mid point joining the charges is -0.8 U. Now +2Q charge is added to each of the point charge. Then potential energy at the same point has a magnitude of
detailed solution
Correct option is D
Initially, U=K(+Q)(−Q2)d=−12KQ2dFinally U1=K(+3Q)(2Q−Q2)d=92.KQ2d⇒U1=9×0.8U=7.2 UTalk to our academic expert!
Similar Questions
Two equal point charges are fixed at x = - and x = + on the X-axis . Another point charge Q is placed at the origin. The change in electrical potential energy of Q when it is displaced by a small distance x along the X-axis, is approximately proportional to
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