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Q.

Two point charges +Q and −Q2 are kept at a separation and potential energy at the mid point joining the charges is -0.8 U. Now +2Q charge is added to each of the point charge. Then potential energy at the same point has a magnitude of

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a

3.2 U

b

2.4 U

c

3.6 U

d

7.2 U

answer is D.

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Detailed Solution

Initially, U=K(+Q)(−Q2)d=−12KQ2dFinally U1=K(+3Q)(2Q−Q2)d=92.KQ2d⇒U1=9×0.8U=7.2 U
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