Two point charges −q and +q are located at points (0, 0, −2a) and (0, 0, 2a) respectively. The electric potential at a point (0, 0, z), where z>a is :
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a
qa4πε0z2
b
q4πε0a
c
4qa4πε0(z2−4a2)
d
2qa4πε0(z2+a2)
answer is C.
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Detailed Solution
Potential at P due to (+q) chargeV1=14πε0.q(z−2a)Potential at P due to (-q) chargeV2=14πε0.−q(z+2a)Total potential at P due to (AB) electric dipoleV=V1+V2=14πε0.q(z−2a)−14πε0q(z+2a)=q4πε0(z+2a−z+2a)(z−2a)(z+2a)⇒ V=4qa4πε0(z2−4a2)