First slide

Electric field

Question

Two point charges Q and-3Q are placed at some distance apart. If the electric field at the location of Q is E, then at the locality of -3Q, it is

Moderate

A

-E
B

E/3
C

3E
D

-E/3

Solution

The field produced by charge -3Q at A is E as mentioned in the question.
$∴ E = \frac{3 Q}{x^{2}}$ (along AB directed towards negative charge)
Now, field at location of -3Q, i.e., field at B due to charge Q will be $E^{'} = \frac{Q}{x^{2}} = \frac{E}{3}$ (along AB directed away from positive charge)

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