Two point charges repel each other with a force of 100 N. One of the charges is increased by 10% and the other is reduced by 10%. The new force of repulsion at the same distance would be
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a
100 N
b
121 N
c
99 N
d
None of these
answer is C.
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Detailed Solution
100=k q1q2/r2 and F=k(1.1q1)(0.9q2)/r2⇒F100=0.99 or F=99 N