Two point charges repel each other with a force of 100 N. One of the charges is increased by 10% and the other is reduced by 10%.The new force of repulsion at the same distance would be
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a
100 N
b
121 N
c
99 N
d
89 N
answer is C.
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Detailed Solution
100 = Kq1q2r2 and F=K(1.1q1)(0.9q2)r2 F100=0.99 ∴F=99N
Two point charges repel each other with a force of 100 N. One of the charges is increased by 10% and the other is reduced by 10%.The new force of repulsion at the same distance would be