Two point masses A and B having masses in the ratio 4 : 3 are separated by a distance of 1 m. When another point mass C of mass M is placed in between A and B, the force between A and C is 13rd of the force between B and C. Then the distance of C from A is:

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23m

13m

14m

27m

answer is A.

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Detailed Solution

FCA=13FCB⇒G4Mmr2=G3Mm(1−r)2×13On solving r=23m