First slide

Gravitaional potential at a point

Question

Two point masses m and 4m are at separation r. P is a point where gravitational field is zero. Then gravitational potential at point P is

Moderate

Solution

$\frac{G . m}{x^{2}} = \frac{G .4 m}{{(r - x)}^{2}} \Rightarrow r - x = 2 x \Rightarrow x = \frac{r}{3}$
$∴ V_{P} = - \frac{G . m}{\frac{r}{3}} - \frac{G .4 m}{\frac{2 r}{3}} = \frac{- 9 G m}{r}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App