First slide

Diffraction

Question

Two points white dots are 1 mm apart on a black paper. They are viewed by eye of pupil diameter 3 mm. Approximately, what is the maximum distance at which these dots can be resolved by the eye ? [Take $λ = 500 nm]$

Moderate

A

6 m
B

5 m
C

3 m
D

1 m

Solution

we know that $θ = \frac{y}{D} \geq \frac{1 \cdot 22 λ}{d}$
or $D \leq \frac{y d}{1 \cdot 22 λ}$
$D \leq \frac{10^{- 3} \times (3 \times 10^{- 3})}{1 \cdot 22 \times 5 \times 10^{- 7}} \leq\approx 5 m D_{max} = 5 m$

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