Two positive charges of magnitude ‘q’ are placed, at the end of a side (side1) of a square of side ‘2a’.Two negative charges of the same magnitude are kept at the other corners. Starting from rest, if a charge Q moves from the middle of side 1 to the centre of square, its kinetic energy at the centre of square is
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a
zero
b
14πε02qQa1+15
c
14πε02qQa1−25
d
14πε02qQa1−15
answer is D.
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Detailed Solution
Potential at point A,VA=2kqa−2kqa5 ∴ (potential due to each q=kaa and potential due to each −q=−kqa5∵2a2+a2=a5Potential at point .B,VB=0 ( ∵ point B is equidistant from all the four charges)∴ Using work energy theorem,(WAB)electric=Q(VA−VB) =2kqQa1−15=14πε02Qqa1−15