Two positively charged particles each of mass 1.7 x 10-27 kg having charge of 1.6 x 10-19 C are placed at separation r. Calculate r (in cm ), to the nearest integer if each one experiences a repulsive force equal to its weight. (Take g = 10 ms-2).
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answer is 12.
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Detailed Solution
mg=q24πε0r2 ⇒ 1.7×10−27×10=9×109×1.6×10−192r2 ⇒r2=9×109×1.6×10−1921.7×10−26 ⇒ r=0.116 m⇒ r=11.6 cm≅12 cm