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Two prisms A and B are in contact with each other have angular dispersions of 200 and 400 respectively. The dispersive power of ‘A’ is 0.002. If the combination produces dispersion without deviation, the dispersive power of ‘B’ is

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a

0.001

b

0.004

c

0.002

d

0.006

answer is B.

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Detailed Solution

δA-δB=0 ⇒∆θAωA-∆θBωB=0⇒ωB=0.002×4020×0.002=0.004

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