Questions
Two projectiles are fired at different angles with the same magnitude of velocity, such that they have the same range. At what angles they might have been projected ?
detailed solution
Correct option is A
We know that, R=u2sin2θgGiven that, R1=R2 and u1=u2∴ R1=u14sin2θg and R2=u22sin290∘−θg∴ sin2θ=sin290∘−θ=cos2θSolving we get, θ=25∘. The other angle is 90∘−25∘=65∘Talk to our academic expert!
Similar Questions
Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.
Reason : Range of projectile does not depend on the initial velocity of a body.
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