Two projectiles are thrown from the same point simultaneously with same velocity $$10$$ $$ms-1$$. One goes straight vertically while other at $$60$$° with the vertical. What will be the distance of separation between the two after $$1$$ second of their throw?

Question

Infinity Learn · Accepted Answer

Here for the projectile thrown at $$60$$° with the vertical.Horizontal velocity $$=$$ $$10$$ $$sin$$ $$60$$° $$=$$ $$53ms$$−$$1vertical$$ velocity $$=$$ $$10$$ $$cos$$ $$60$$° $$=$$ $$5$$ $$ms-1Horizontal$$ separation Δ$$x=53$$×$$1=53Vertical$$ separation $$=$$ $$h1$$ $$-$$ $$h2$$Δ$$y=10t$$−$$12gt2$$−$$5t$$−$$12gt2=(10$$×$$1$$−$$5$$×$$1)=5m$$∴displacement |r|$$=(53)2+52=10m$$

Two projectiles are thrown from the same point simultaneously with same velocity 10 ms^-1. One goes straight vertically while other at 60° with the vertical. What will be the distance of separation between the two after 1 second of their throw?

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Two projectiles are thrown from the same point simultaneously with same velocity 10 ms-1. One goes straight vertically while other at 60° with the vertical. What will be the distance of separation between the two after 1 second of their throw?

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Two projectiles are thrown from the same point simultaneously with same velocity 10 ms^-1. One goes straight vertically while other at 60° with the vertical. What will be the distance of separation between the two after 1 second of their throw?