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Q.

Two radioactive substance A and B have decay constants 9λ and 3λ respectively. At t = 0 , they have the same number of nuclei. The ratio of number of nuclei of A to these of B will be 1e2 after a time interval of

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a

12λ

b

15λ

c

14λ

d

13λ

answer is D.

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Detailed Solution

Decay Law, N = Noe-λt Case 1 : N1=Noe−λ1t=Noe−9λt Case 2 : N2=Noe−λ2t=Noe−3λt Dividing them, N1N2=Noe-9λtNoe−3λt=e−6λt But N1N2=1e2 ⇒ e−6λt=e−2 ⇒6λt=+2 ⇒t=26λ=13λ

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