Questions
Two rectangular plates A and B placed at a distance 2a apart, are connected to a battery to produce an electric field. There are insulators between plates C and other two plates. A magnetic field exists along z-axis. A charged particle of mass m and charge q passes through a hole at the middle of the plate A with velocity v and strikes at Q which is the middle of the bottom edge of plate B after passing through a hole in plate C. If E=m v^{2} / q a what will be the speed of the particle at Q?
detailed solution
Correct option is C
Work done =qE.2a= change in KE q·mv2qa·2a=12mvQ2-12mv2 4v2=vQ2-v2⇒vQ=v5Talk to our academic expert!
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