Two resistance 20 Ω and 50 Ω and a pure inductance of 50 H are connected to a 10 V battery through a key as shown in the figure. The key is tapped at t = 0. Find the final value of current in the 50 Ω resistor :
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a
Zero
b
1/7 A
c
110A
d
0.5 A
answer is A.
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Detailed Solution
Since inductance is purely non-resistive, the final current when approaches to its maximum value will flow directly through the inductance and there will be no current in the 50 Ω resistor.